y^2-0.6y=-0.08

Solution for y^2-0.6y=-0.08 equation:

y^2-0.6y=-0.08

We move all terms to the left:

y^2-0.6y-(-0.08)=0

We add all the numbers together, and all the variables

y^2-0.6y+0.08=0

a = 1; b = -0.6; c = +0.08;
Δ = b2-4ac
Δ = -0.62-4·1·0.08
Δ = 0.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.6)-\sqrt{0.04}}{2*1}=\frac{0.6-\sqrt{0.04}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.6)+\sqrt{0.04}}{2*1}=\frac{0.6+\sqrt{0.04}}{2}
$